7x^2-19x-26=0

Solution for 7x^2-19x-26=0 equation:

7x^2-19x-26=0

a = 7; b = -19; c = -26;
Δ = b2-4ac
Δ = -192-4·7·(-26)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-33}{2*7}=\frac{-14}{14}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+33}{2*7}=\frac{52}{14}
=3+5/7
$